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 dy/dx does not exist at y=0 Finding dy/dx takes a bit more work Beginning with y^2=(x^24)/(x^24) we differentiate to get 2y dy/dx = "some function of "x But then dy/dx requires dividing by y, so it is not defined at y = 0 In detail 2ydy/dx = (2x(x^24)2x(x^24))/(x^24)^2 2ydy/dx = (16x)/(x^24)^2 dy/dx = (8x)/(y(x^24)^2)# Here is the graph of the equation graph{y^2(x^24)/(x^2Graph y=2(x4)(x2) Find the properties of the given parabola Tap for more steps Rewrite the equation in vertex form Tap for more steps Complete the square for Tap for more steps Simplify by multiplying through Tap for more steps Apply the distributive property Multiply by4 (((((x 2)(y 2))4x)——)y 2)4x)4 x 2 Step 2 Rewriting the whole as an Equivalent Fraction 21 Subtracting a fraction from a whole Rewrite the whole as a fraction using x 2 as the denominator Graph Y 1 4 X 2 Youtube Y=x^2 y=-x^2+4x

$\begingroup$ Your answer and another comment made above made it clear I was wrong in attempting to use the derivative of the function as the slope of the tangent That was my mistake How silly However, while I can see how I'd get the slope and use it, and that your equation y2 = 3(x1) does become y = 3x1 (The slope)Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, historyI did x^24x4=64 (x2)^2=2 x2=±√2 Am I doing it right? Draw The Graph Of Y 2x 2 3x 5 And Hence Solve 2x 2 4x 6 0 Y 2x 2 3x 5 Sarthaks Econnect Largest Online Education Community Y=9-x y=2x^2+4x+6